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9 years ago, I was five times as old as my eldest son. Today I am 3 times his age. HOW old am I now? Express my age in binary numbers
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- if we considor todays sons age=x and fathers age=y
then first equation
y=3x
and 9 year ago
5(x-9)=y-9
then put y=3x
then we get 2x=36
x=18
and hence y =3x=54
so binary representation for 54=110110 ans - 12 years agoHelpfull: Yes(15) No(5)
- let us consider
son = x yrs father(me)= 3x
before 9 yrs
son =x-9 father=3x-9
now equate it
(x-9)=5(3x-9)
solve it x=18(10010) so my age is 54(110110) now convert urself it will be
- 12 years agoHelpfull: Yes(5) No(2)
- 9 yrs ago
eldest son age be 'x'
my age '5x'
9 years back
eldest son age 'x+9
my age '5x+9'
by the problem
5x+9 = 3(x+9)
x=9
my age 5x=5*9=45
in binary
101101
- 12 years agoHelpfull: Yes(3) No(14)
- son age=x years
father age=5x years 9 years ago
now 5x+9=3(x+9)
so x=9 years
father age=54 years
in binary 110110 - 11 years agoHelpfull: Yes(2) No(1)
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