three times the present age of mike is equal to eight times the present age of his son john.eight yrs hence mike will be twice as old as his son at that time.what are their present ages?

• present age mike = x and john = y
  3x=8y
  x+8=2(y+8)
  by multiplying both side 4 we get
  4x+32=8y+64
  4x=3x+32
  ages are
  x=32
  y=3*32/8=12
  
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