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the sum of ages of leo and his son jan is 45yrs . five yrs ago the product of their ages was four times leo age at that time.the present age of leo is?

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five yrs ago the product of their ages was four times leo age at that time.

It means, 5 years ago, age of son was 4 years.
Present age of son = 4+5=9 yrs
present age of leo = 45-9=36 years.
12 years agoHelpfull: Yes(19) No(2)

Ans 30 years
If the present age of Leo=x ,Jan=y
Given condition x+y=45 and (x-5)(y-5)=4(x-5)) -> xy-9x-5y+45=0
Substituting value of y=x-45 ->x(45-x)-9x-5(45-x)+45=0
x^2-41x+180=0 ->(x-36)(x-5)=0
Thus Leo's age x=36 and Jan's age y=9
12 years agoHelpfull: Yes(14) No(3)

TCS Other Question

three times the present age of mike is equal to eight times the present age of his son john.eight yrs hence mike will be twice as old as his son at that time.what are their present ages? a father tom`s age is three times the sum of the ages of his two children,but 20yrs hence his age will be equal to the sum of their ages.then the father tom age is?