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in a g.20 meeting there were total 20 people representing their own country all the representatives sat around a circular table.the no. of ways we can arrange them in a circular table such that 1 person is always there in between manmohan and musharaf.
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- treat that manmohan,musharraff,the one person as a single group..
so 18(17persons+1group)can be arranged in 17! ways
now manmohan and musharraff can exchange their places therefore 2 ways
therefore 17!*2 is the answer - 12 years agoHelpfull: Yes(23) No(2)
- let us take manmohan one person musharaf as one person so total number of person=18
so they can be arranged in circular tabl in =(18-1)!=17! - 12 years agoHelpfull: Yes(6) No(5)
- now manmohan and musharraf can be seated as =19C2 (1 space between them rest 19)
now 18 people can be seated as = 18!
so total ways = 19C2 x 18! ans - 12 years agoHelpfull: Yes(5) No(9)
- select 18 mem bw 2mem then 2*18*17!=
- 12 years agoHelpfull: Yes(5) No(0)
- first arrange manmohan and musharaf
manmohan can sit in 20 ways so musharaf can occupy only two places wrt the condition
the remaining 18 people can sit on the table in 18! ways
so total no of ways=20*2*18! ways - 12 years agoHelpfull: Yes(4) No(0)
- ans is =17!*18c2
- 12 years agoHelpfull: Yes(2) No(3)
- excluding manmohan and musharaf we have 18 persons to select between them.. hence select one person in 18 to sit between them. now consider the selected person and manmohan and musharaf as a single unit
total arrangements = 18C1*(18-1)!
= 18! - 12 years agoHelpfull: Yes(0) No(4)
- ans is 20c3x16!
- 12 years agoHelpfull: Yes(0) No(4)
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