how many 4 digits no can be formed with digits 1,2,3,4,5 which are divisible by 4 and digits not be repeated?

• for last 2 places there are 4 options that are 12,24,32, and 52
  now 2 places are to be fill and we 3 options to fill one and two options for other.
  the solution is 3*2*4=24
• 12 years agoHelpfull: Yes(6) No(3)
• 1,2,3,4,5 its divisible by 4 means last 2 digit are divisible by 4
  means 12,24,32,52(4 possibility to divisible by 4)
  remaining 3 place can be filled in 3*2*1 ways for each.
  total 4 digit no. formed=4*3*2*1=24
  ans:24
• 10 years agoHelpfull: Yes(3) No(0)
• 5 digit no -----
  12,24,32 are divisible by 4,so last 2 blanks can be filled in 3 ways
  now there are 3 no and 3 blanks 1st blank can be filled in 3 ways repetition is not allowed so 2nd blank in 2 ways and 3rd in 1 way
  3*2*1*3=18 ways
• 12 years agoHelpfull: Yes(1) No(6)
• there are number which have last two digit is : 12,32,52 and 24
  so solution is 2!*4=8;
• 12 years agoHelpfull: Yes(0) No(6)
• sorry above solution is not correct!!!!
• 12 years agoHelpfull: Yes(0) No(5)
• there are 80 no. which are diviible by 4!!
  5*4*4
• 12 years agoHelpfull: Yes(0) No(6)
• correct answer=3p3*4=24
• 8 years agoHelpfull: Yes(0) No(0)
• correct answer=3p3*4=24
• 8 years agoHelpfull: Yes(0) No(0)
• correct answer=3p3*4=24
• 8 years agoHelpfull: Yes(0) No(0)
• correct answer=3p3*4=24
• 8 years agoHelpfull: Yes(0) No(0)
• correct answer=3p3*4=24
• 8 years agoHelpfull: Yes(0) No(0)
• correct answer=3p3*4=24
• 8 years agoHelpfull: Yes(0) No(0)
• for last 2 places there are 4 ways that are 12,24,32, and 52=4!=24
  Reaming are 3 places which can be arrange in 3 ways=3!=6
  final solution=24*6=144
• 7 years agoHelpfull: Yes(0) No(1)