if a tap could fill entire tank in 18 hrs due to leakage, then in how much time tank can be emptied by leakage if tap can fill entire tank in 12 hrs without leakage?

• if a tap could fill entire tank in 18 hrs due to leakage,
  tap can fill entire tank in 12 hrs without leakage.
  Tank emptied in 0ne hr by leakage = 1/12-1/18= (6-4)/72=2/72=1/36.
  Full Tank can be emptied in 36 hrs.
• 13 years agoHelpfull: Yes(10) No(0)
• let A be the time in which the the tank can be filled without leakage and B be the time in which it is emptied. A=12hrs, the work done by A is 1/A i.e. 1/12 and 1/A - 1/B=1/18.
  1/12-1/18=1/B
  B=36hrs
• 13 years agoHelpfull: Yes(0) No(1)
• 36 hours
  (1/12)-(1/18)=1/36
• 13 years agoHelpfull: Yes(0) No(0)
• total 36 hours
• 3 years agoHelpfull: Yes(0) No(0)