the probability of a student possessing a ball point pen in exam is 3/5 & possessing an ink pen is 2/3. find his probability of possessing at least one of them

• the probability of a student possessing a ball point pen in exam is 3/5 .
  the probability of a student not possessing a ball point pen in exam is 2/5 & possessing an ink pen is 2/3.
  
  & not possessing an ink pen is 1/3.
  his probability of possessing none of them =2/5*1/3=2/15
  his probability of possessing one of them =1-2/15 = 13/15
  
• 13 years agoHelpfull: Yes(34) No(3)
• * may be probability of possessing atleast one of them is 13/15.
  * probability of possessing atleast one of them is
  =1-probability of not possessin any pen
  =1-((1-3/5)*(1-2/3))
  =1-(2/5)*(1/3)
  =1-(2/15)
  =13/15
• 13 years agoHelpfull: Yes(10) No(2)
• 2/5*1/3=2/15
  there fore, 1-2/15 = 13/15
• 12 years agoHelpfull: Yes(9) No(3)