In a game of 100 points there are three participants A, B, and C. A gives to B 10 points and to C 19 points, then how many points can B give to C

• A:B=100:90 (A can give 10 points to B means A is 10 points leads to B and from the problem A=100)
  A:C=100:81
  
  for B:C
  
  B:C = (A:C)*(B:A)
  = (100/81)*(90/100)
  =10/9
  = 10:9
  multiply and devide by 100
  B:C = 100:90
  
  B can give 10 points to C
• 10 years agoHelpfull: Yes(41) No(2)
• 9 POINTS
  A=B+10,A=C+19,=> B+10=C+19,=> B=C+9
• 13 years agoHelpfull: Yes(33) No(17)
• A B C
  100 90 81
  90/9=10 81/9=9
  10*10=100 9*10=90
  so in the case of B,c B gives 10points to c
• 10 years agoHelpfull: Yes(3) No(4)
• a=b+10,a=c+19=>b+10=c+19
  b=c+9
  
• 9 years agoHelpfull: Yes(3) No(0)
• a/b=100/90
  a/c=100/81
  b/c=b/a*a/c
  100/c=90/100*100/81
  c=90 b gives c 100-90=10 pts
• 10 years agoHelpfull: Yes(2) No(2)
• 100/90(A to B)
  100/81(A to c)
  B to C=90/81(as it is 100 points game no need of conversion otherwise convert it)
  ans is 90-81=9
• 10 years agoHelpfull: Yes(1) No(5)