In a group of 25, 13 can speak Latin, 15 can speak French, and 6 don't speak either. How many of these speak both Latin and French?

• LET N(A) BE THE PEOPLE WHO SPEAK LATIN AND LET N(B) BE THE PEOPLE WHO SPEAK FRENCH
  N(A^B) OR MEANS TO SAY A INTERSECTION B
  THEN BY FORMULA
  N(A UNION B)=N(A)+N(B)-N(A^B)+6
  25=13+15-X+6
  X= 28+6-25
  X=9
  9 PEOPLE SPEAK BOTH...
  
  
• 13 years agoHelpfull: Yes(27) No(6)
• let no.of persons who speeks booth latin and french = x
  so, no.of persons who speeks only latin = 13-x
  no.of persons who speeks only french= 15-x
  no.of persons who speeks dont speek any lag = 6
  therefore (13-x)+(15-x)+x+6=25
  34-x=25
  x=9;
• 13 years agoHelpfull: Yes(20) No(2)
• In a group of 25, 13 can speak Latin, 15 can speak French, and 6 don't speak either. So there are 19 persons, who can speak in any one language or both languages . So persons speaking both languages = 13+15-19= 9 .
• 13 years agoHelpfull: Yes(10) No(3)
• ans is 9
  n(AUB)=25-6=19(people who speak any language
  people who speak both=13+15-19=9
• 10 years agoHelpfull: Yes(5) No(0)
• 9
  given: n(AUBUC) = 25
  n(A)=13; n(B)=15; n(C)=6
  therefore no.of person who speak both latin and french are
  25 = 13+15+6-x
  therefore x=9.
• 13 years agoHelpfull: Yes(4) No(1)
• so only 19 people can speak either of them so only 9 people can speak both latin and french
• 13 years agoHelpfull: Yes(2) No(1)
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• 7 years agoHelpfull: Yes(0) No(0)