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Q. 2 friends A n B running up hill and then to get down length of road 440 yads A on his return journey met B going up at 20 yards from top if A has finished race 5 minute earlier than B then how much time A had taken to complete the race ?
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- total journey= 440*2=880
A meet B 20 yards from top in getting down it means he has covered 440+20=460 yards while B is 420 yards.so he is 40 yards ahead of B which is equals to 5 minute.
so 40 yards in 5 min
880 yards will be in 5*880/(40)=110 minute - 9 years agoHelpfull: Yes(5) No(5)
- 50 mins, first find Va/Vb then Ta= t-5, Tb= t
- 8 years agoHelpfull: Yes(3) No(0)
- When A travels 460m (=440+20),
B travels 420m (=440-20). So, ratio of speed = 460:420
= 23:21.
Let A's speed be 23x, and that of B's be 21x.
=> 23x = ((2 * 440) / t) which implies 23t = 880/x;
=> 21x = ((2 * 440) / (t+5)) which implies 21(t+5) = 880/x.
From these two equations, 23t = 21(t+5). Solving, t = 52.5 - 6 years agoHelpfull: Yes(0) No(0)
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