A rectangular plot of lawn of length and width respectively x and y metres is surrounded by a pathway of

(x+4)(y+4)-xy= 4x+4y+16
11 years agoHelpfull: Yes(6) No(0)
(A)2x+2y+4
area of the pathway=(x+2)*(y+2)-x*y
x*y+2x+2y+4-x*y
2x+2x+4
11 years agoHelpfull: Yes(3) No(10)
the total area of pathway is: ((x+4)(y+4)-(x*y))=4x+4y+16
11 years agoHelpfull: Yes(2) No(0)
1st time area of rect = xy
2nd time area of rect = (x+2+2)(y+2+2)=(x+4)(y+4)
=4x+4y+xy+16

area of pathway = total inc area - old area
= (4x+4y+xy+16) - xy
=4x+4y+16
10 years agoHelpfull: Yes(2) No(0)
How come x+4? pathway width is only 2mts na?
10 years agoHelpfull: Yes(2) No(0)
correct ans. is D
cause area of pathway=area of lawn+pathway-area of lawn=(x+4)*(y+4)-x*y=4x+4y+16
11 years agoHelpfull: Yes(1) No(0)
how become Length and width of outer rectangle = (x + 4) , (y + 4)?
10 years agoHelpfull: Yes(1) No(0)
Total area=path area +rect area=(x+4)*(y+4);
path area= total area- rect area;
hence D
8 years agoHelpfull: Yes(0) No(0)

A rectangular plot of lawn of length and width respectively x and y metres is surrounded by a
pathway of 2 metres width. The total area of pathway is :

(A) 2x + 2y + 4

(B) 2x + 2y + 8

(C) 4x + 4y + 8

(D) 4x + 4y + 16