The average weight of three men A, B and C is 84 Kg. The average weight becomes 80 Kg when D joins them. If E whose weight is 3 Kg more than D joins the group replacing A, then the average weight of B, C, D and E becomes 79 Kg. The weight of A is:
(a)65kg (b)70kg (c)75kg (d)80kg

• 75 kg
  
  Wt of ABC = 84*3= 252 kg
  wt of ABCD= 80*4=320 kg
  wt of D= 68 kg
  wt of E = 71 kg
  wt of ABCDE = 320+71=391 kg
  wt of BCDE = 79*4=316 kg
  wt of A = 391-316=75 kg
• 13 years agoHelpfull: Yes(6) No(2)
• 75 kg d weight=80*4-84*3=68
  e weight=68+3=71kg
  b,c,d.e er weight=316-(68+71)=177kg aweight=252-177=75kg
  ans
  
• 13 years agoHelpfull: Yes(2) No(2)
• 75 kg
  (a+b+c)/3=84
  (a+b+c+d)/4=80
  (b+c+d+e)/4=79 which is (b+c+d+d+3)/4=79
  now a+b+c=252
  substituting in 2nd equation d=68 so e=71
  substituting value of d and e in 3rd euation we get b+c=177
  a+177=252 hence a=75kg
• 13 years agoHelpfull: Yes(2) No(2)
• a+b+c=84*3=252
  a+b+c+d=80*4=320
  so d=320-252=68
  e=68+3=71
  b+c+68+71=79*4=316
  b+c=316-139=177
  a+b+c=252
  so a=252-177=75
• 13 years agoHelpfull: Yes(2) No(1)