MBA Exam

What is the ratio of area of an equilateral triangle and total surface area of a cuboid where the equilateral triangle is made by taking side equal to the longest rod that can be placed in the cuboid 12 m long, 9 m broad and 8 m high?

1) 289âˆš3 : 2208
2) 17âˆš3 : 36
3) 17 : 29
4) 29âˆš3 : 2208
5) None of these

Read Solution (Total 1)

289 root3: 2208

side of triangle = root (12^2+9^2+8^2)=17 m
Area of triangle = ((root3)*17^2)/4 = (289 root3)/4
Area of cuboid = 2*( 108+72+96)=552 sq mtr

Ratio of areas= ((289 root3)/4)/552 = 289 root3/ 2208 or 289 root3: 2208
11 years agoHelpfull: Yes(0) No(0)

MBA Other Question

How many times would zero be used while writing all the natural numbers from 1 to 63 in the Binary System?
(a) 32 (b) 80 (c) 111 (d) 129

1) a
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The surface of a right circular cone is painted black. The cone has height 4 and its base has radius 3. It is cut into two parts by a plane parallel to the base, so that the volume of the top part (the small cone) divided by the volume of the bottom part (the frustrum) equals the painted area of the top part divided by the painted are of the bottom part. The height of the small cone is

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