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Time Distance and Speed
Two pipes A and B can fill a tank in 24 min. and 32 min. respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 minutes?
Read Solution (Total 11)
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- a 1 day work 1/24
b 1 day work 1/32
since the work is completed in 18 min and we have to be closed after some time ,pipe a fill pipe for whole 18 min ,a 18 min work is 18/24=3/4
remaining work 1/4 which is completed by b
so b should be closed after 32/4=8 min - 9 years agoHelpfull: Yes(11) No(0)
- x(1/24+1/32)+(18-x)1/24=1
ans=8min - 9 years agoHelpfull: Yes(6) No(1)
- after 8 min
- 9 years agoHelpfull: Yes(3) No(2)
- let size of tank=96m (lcm of 24 & 32) , then speed of A for 1min=96/24=4m/min & B=96/32=3m/min
then when both pipes are opened speed is=3+4=7m/min
let Xm tank is filled when both pipes are opened & (96-X)m tank is filled when only pipe A is opened..
X/7+(96-X)/4=18
so X=56, then 56/7 time pipe B is opened... i.e 8 min & after 8min pipe B is closed
so pipe A required (96-56)/4=10min
total=10+8=18
ans.=8min - 9 years agoHelpfull: Yes(3) No(0)
- let size of tank=96m , then speed of A for 1min=96/24=4m/min & B=96/32=3m/min
then when both pipes are opened speed is=3+4=7m/min
let Xm tank is filled when both pipes are opened & (96-X)m tank is filled when only pipe A is opened..
X/7+(96-X)/4=18
so X=56, then 56/7 time pipe B is opened... i.e 8 min & after 8min pipe B is closed
so pipe A required (96-56)/4=10min
total=10+8=18
ans.=8min - 9 years agoHelpfull: Yes(1) No(0)
- let a and b work together for x mins
a 1 min work=1/24
b 1 min work=1/32
a+b 1 min work=1/24+1/32=7/96
a+b x min work=7x/96
as given,7x/96+(18-x)*1/24=1
x=8 min
- 8 years agoHelpfull: Yes(1) No(0)
- a completed work in 18 min=18/24=3/4
So remaining work=1-(3/4)=1/4
x((1/24)+(1/32))=(1/4)
then we will get x=24/7 then and:24/7 - 9 years agoHelpfull: Yes(0) No(2)
- explain it clearly
- 9 years agoHelpfull: Yes(0) No(0)
- thnk u@ swapnali pawar
- 9 years agoHelpfull: Yes(0) No(0)
- let a and b work together for x mins
a 1 min work=1/24
b 1 min work=1/32
a+b 1 min work=1/24+1/32=7/96
a+b x min work=7x/96
as given,7x/96+(18-x)*1/24=1
x=8 min
- 8 years agoHelpfull: Yes(0) No(0)
- 6 minutes...A=1/24,B=1/32
K(1/24+1/32)+18*1/32=1
K=6 - 8 years agoHelpfull: Yes(0) No(0)
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