TCS
Company
Numerical Ability
Averages
The average of a list of 6 numbers is 20. If we remove one of the numbers, the average of the remaining numbers is 15. What is the number that was removed?
Read Solution (Total 21)
-
- Removed number is 45
soln:
6*20=120
new average,
15*5=75
so
removed number is (120-75)=45 - 9 years agoHelpfull: Yes(10) No(1)
- let us assume sum of 6 numbers is x.
so equation is x/6=20
x=120--------(1)
and let us consider r is number which removed so it remove from the sum of 6 numbers and left only 5 number
so average of 5 number is eq. (x-r)/5=15
x-r=75-----------(2)
from (1) and (2)
x-x+a=120-75
then a=45
so answer is 45.
- 9 years agoHelpfull: Yes(2) No(0)
- 45
x1+x2+x3+x4+x5+x6=120
x1+x2+x3+x4+x5=75
x6=120-25=45 - 9 years agoHelpfull: Yes(0) No(0)
- sum=avg*num
sum=20*6=120
after removing num
sum=15*5=75
removing num=120-75=45 - 9 years agoHelpfull: Yes(0) No(0)
- 45
6 nos sum = 20*6 =120
120-x =15*5=75
x =45 - 9 years agoHelpfull: Yes(0) No(0)
- effective change 5*6=30
the no=30+15 - 9 years agoHelpfull: Yes(0) No(0)
- 6*20=120
5*15=75
no.=120-75=45 - 9 years agoHelpfull: Yes(0) No(0)
- let the total be x
when the avg is 20 and nos. are 6, then total = 6*20=120
now one no is removed hence nos . are 5 and avg is 15,
therefore new total = 15*5=75,
therefore the removed no is (120-75)=45 - 9 years agoHelpfull: Yes(0) No(0)
- average=sum/count, sum(6 nos)=120,sum(5 nos)=75
number is 45 - 9 years agoHelpfull: Yes(0) No(0)
- (x+y)/6=20 , where x is addition of 5 no. and y is the 6th no.
and
y/5=15 then x=45
so that no. is 45 - 9 years agoHelpfull: Yes(0) No(0)
- 120-x=15*5
x=45 - 9 years agoHelpfull: Yes(0) No(0)
- solution:
6*20=120
5*15=75
so, the removed number is (120-75)=45 - 9 years agoHelpfull: Yes(0) No(0)
- sum1=20*6 and sum2=sum1-x=15*5
20*6 -x = 15*5
x= 120 - 75= 45 - 9 years agoHelpfull: Yes(0) No(0)
- 20*6-15*5=45
- 9 years agoHelpfull: Yes(0) No(0)
- 20*6=120
15*5=75
120-75=45 - 9 years agoHelpfull: Yes(0) No(0)
- (6*20)-(5*15)=45
- 9 years agoHelpfull: Yes(0) No(0)
- 42.5 is right answer
- 9 years agoHelpfull: Yes(0) No(0)
- 20+5*5=45 .the no is giving the avg of 20.also the no is able to give 5 to each remainng five no so no is
- 9 years agoHelpfull: Yes(0) No(0)
- 20*6=120
5*15=75
120-75=45 - 8 years agoHelpfull: Yes(0) No(0)
- (A+rem)/6=20..A+rem=120
rem/5=15..rem=75.and
A=45.. - 8 years agoHelpfull: Yes(0) No(0)
- avg=sum/no of item
20=x/6
x=6*20=120
avg=sum/no of item
15=y/5
y=15*5=75
the required no is =120-75=45 - 7 years agoHelpfull: Yes(0) No(0)
TCS Other Question