Ten years ago X was half of Y. If the ratio of their present ages is 3:4, what will be the total of their present ages?

• let the present age of X and Y be x,y
  x:y=3:4
  x-10=1/2(y-10)
  on solving the equations we get
  x=15,y=20
  so total =35
• 9 years agoHelpfull: Yes(12) No(0)
• X present x
  Y present x
  X=3,Y=4
  (3x-10) = 1/2(4x-10)
  2(3x-10)= (4x-10)
  6x-4x=20-10 -> 2x=10 ->x=5
  .
  . . 3x + 4x
  ->3*5 +4*5
  15+20=35
  
• 9 years agoHelpfull: Yes(4) No(0)
• let present age of X is x/2
  present age of Y is x
  then
  X Y
  x/2 - 10 x-10
  3 4
  on cross multiplication, we get
  4((x/2)-10) = 3(x-10)
  2x-10 = 3x-30 => x = (-) 10
  present age of Y is x = 10 + 10 = 20
  present age of X is x/2 = 5 + 10 = 15
  total ages of X & Y is 15+20 = 35
  
  
• 9 years agoHelpfull: Yes(3) No(0)
• Present ages X , Y
  Ten years ago : X-10 = (Y-10) / 2 ---- (1)
  Present age ratio X:Y = 3:4 -----------(2)
  Solving 1 & 2
  Y = 20, X=15
  Total X+ Y =35
  
• 9 years agoHelpfull: Yes(1) No(0)
• Let the present age of X be x.
  age of X ten years ago was (x-10)
  age of Y ten years ago was 2(x-10) as because Y is twice as big as X
  
  So the case before ten years is (x-10)=2(x-10)
  So the case at present is (x-10)+10=2(x-10)+10 i.e x= 2x-10
  
  
  hence by ratio,
  
  3/4=x/(2x-10)
  by solving, x=15.
  
  sub in 2x-10 we get age of y as 20
  x+y = 20+15=35.
• 9 years agoHelpfull: Yes(1) No(0)
• 35 explanation : ( 3x-10)=1/2(4x-10)
• 9 years agoHelpfull: Yes(1) No(0)
• Let Current Age Of X And Y is x and Y.
  So,Ten Years Ago,
  X's Age=x-10.
  Y's Age=y-10.
  
  According to Question,
  x-10=1/2(y-10)
  On Solving this,
  2x-y=10--------->1
  and It is Given That
  x:y=3:4
  or x=3/4y---------->2
  On Solving 1 and 2
  x=15,y=20
  x+y=35
  
  
• 9 years agoHelpfull: Yes(1) No(0)
• (X-10)=(Y-10)/2 and X/Y=3/4
  X=15,Y=20
  TOTAL 35 YEARS
• 8 years agoHelpfull: Yes(1) No(0)
• ans 30
  x=1/2y eq1
  x:y is given 3:4
  by subsituting the value of x in eq1
  y=20
  then x=10
  sum of their present age 30
  
• 9 years agoHelpfull: Yes(0) No(0)
• x=15,y=20 4x=3y and 2(x-10)=(y-10)
• 9 years agoHelpfull: Yes(0) No(0)
• Total age is 14
• 9 years agoHelpfull: Yes(0) No(1)
• present ages be x,y
  given: x=10= 1/2(y=10)
  x:y=3:4
  so solving we get, x=15, y=20
  so, present age is 35
  
• 9 years agoHelpfull: Yes(0) No(0)
• let the past age of X and Y be x,2x
  after 10years their ages are (x+10), (2x+10) respectively
  (x+10)/(2x+10)=3/4
  on solving the equations we get
  x=5
  present age of X is (5+10)=15years
  present age of Y is (2*5)+10=20years
  total=15+20=35 years
• 9 years agoHelpfull: Yes(0) No(0)
• y=20 and x=15
• 9 years agoHelpfull: Yes(0) No(1)
• answer is 35
  let the present age of X be x and that of Y is y.
  now x/y=3/4
  x-10=(y-10)/2
  solving the two equatins we get y=20 and x=15 hence x+y=35
• 9 years agoHelpfull: Yes(0) No(0)
• let the ages of X and Y 10 years ago be X and Y
  X=1/2Y
  After 10 years their ages would be X+10 and Y+10 which is their present ages
  now,
  (X+10)/(Y+10)=3/4
  Solving this we get,Y=10
  and X=5
  Now their present ages would be: X+10=5+10=15
  and Y+10=10+10=20
  Sum of their ages =15+20=35
• 9 years agoHelpfull: Yes(0) No(0)
• let present age is 3x,4x
  ten years ago
  2(3x-10)=4x-10
  x=5
  so present age are 15 and 20
  so sum=35
• 9 years agoHelpfull: Yes(0) No(0)
• sum of ages=35
  ten years ago: ages= 5 and 10 (1:2)
  present ages= 15 and 20 (3:4)
  sum= 15+20 = 35
• 9 years agoHelpfull: Yes(0) No(0)
• suppose the present age of X=a+10 and Y=2a+10
  therefore a+10/2a+10=3/4
  on solving the equations we get X=15,Y=20
  so total age+35
• 9 years agoHelpfull: Yes(0) No(0)
• x-10=0.5(y-10)
  4x=3y
  3y-40=2y-20
  y=20
  x=15
• 7 years agoHelpfull: Yes(0) No(0)
• ans is 35
  the age of X and Y 10 yrs ago be x and 2x
  then,
  (x+10)/(2x+10)=3/4
  4(x+10)=3(2x+10)
  2x=10
  x=50
  therefore,sum of their present ages =(x+10)+(2x+10)
  =3x+20
  =3*5+20
  =35 yr
• 7 years agoHelpfull: Yes(0) No(0)
• answer is 35
• 6 years agoHelpfull: Yes(0) No(0)