Find the number of consecutive zeroes immediately after the decimal in 1/20^37PS : Not Providing the log values..It is suggested to remember Log2,3 and 5

1) 47
2) 48
3) 49
4) 46

• first (1/20)^37 taking log to this will give log(1/20)^37
  
  this can be written as (log1-log20)^37
  
  log 1=0
  
  log 20 can be written as -(log 2+log 10)^37
  
  log 10 = 1 log 2=0.3010
  10
  
  -37(1+0.3010)
  =-48
  
  As we are calculating for the zeroes after decimal the anwer will have negative symbol
  
  these are the formulas used am giving in the order
  log(a/b)=log a -logb
  loga^m=mlog a
  loga*b=log a+logb
  
• 10 years agoHelpfull: Yes(1) No(0)