varun is guessing which of the 2 hands holds a coin. what is the probability that varun guesses correctly three times in a row?
a. 1/6 b. 1/2 c. 1/4 d. 1/8

• Ans will be 1/8. as there are 2 hands to hide the coin and it can be in 1 of them. so the prob of guessing or the coin be in either of 1 hand is 1/2.[here 1(i.e. 1 hand) is the outcome & 2(i.e. both or 2 hands) is the possible outcomes, prob= outcome/possible outcomes].Now 3 times in a row i.e. the same work is being performed 3 times to perform the whole task given in qstn. So, (1/2)(1/2)(1/2)=1/8
• 9 years agoHelpfull: Yes(35) No(0)
• 2 Coin= prob is 4
  
  And Men=1
  
  So according to formula = 1/4
  
  
  1/4 is Correct Answer
• 9 years agoHelpfull: Yes(4) No(15)
• Prob will be 1/2
  Option b
• 9 years agoHelpfull: Yes(3) No(4)
• Probability of coin tossing is =1/2
  No.of.times=3
  Probability of tossing a coin 3 times = 1/2*1/2*1/2
  = 1/8
• 6 years agoHelpfull: Yes(3) No(0)
• explain @aman
  
• 9 years agoHelpfull: Yes(2) No(0)
• Do it as smart way
  P = n(E)/n(S)
  Tossing a coin 3 times so total no.of outcumes is 8
  Varun guess possibility is 1
  1/8
• 7 years agoHelpfull: Yes(2) No(1)
• @anand there is only one coin not two.pls check your solution
• 9 years agoHelpfull: Yes(1) No(0)
• d.1 /8 because we have to attempt three times hence there will be 8 sample space from which we have to find( RRR) such as three coins ar etossed and have to probability of (HHH).
• 9 years agoHelpfull: Yes(1) No(1)
• c. 2C1/8=1/4
• 7 years agoHelpfull: Yes(0) No(1)
• 1/4
  4c3=1/4
• 6 years agoHelpfull: Yes(0) No(1)