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two coins are flipped & atleast one of the output is known to be head,wat is d probability that both outcomes are head.
Read Solution (Total 11)
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- as it is fixed that one of the outcome is head.
sample space for flipping of two coins = {(H,T),(T,H),(H,H)}
P(TWO HEADS) = 1/3 - 13 years agoHelpfull: Yes(26) No(2)
- out comes occur={(h,h),(h,t),(t,h),(t,t)}
=4.
at least one of the output head=3.
p=3/4. - 13 years agoHelpfull: Yes(5) No(4)
- 1/2
two coins are flipped & atleast one of the output is known to be head,
probability of getting head on other coin =1/2.
probability that both outcomes are head = 1*1/2=1/2.
- 13 years agoHelpfull: Yes(3) No(3)
- Two coins are flipped.
One is shown head. So here we already got head. The probability is = 1.
Another one is either head or tail. So probability of getting head is =1/2.
So total probability is =1+1/2
=3/2. - 13 years agoHelpfull: Yes(3) No(17)
- as it is fixed that one of the outcome is head.
then we have already fixed that either we have sample space{(h,t),(h,h)}or{(t,h),(h,h)}
so, p(two heads)=1/2 - 13 years agoHelpfull: Yes(3) No(4)
- Pls check this qn. How many 4 or 5 digit numbers can be formed by using 0, 1, 3, 5, 8. Repetition is not allowed. None of the given options is correct. No. of 4 digit nos that can be formed by using 0, 1, 3, 5, 8.( Repetition is not allowed.)=4*4*3*2=96 No. of 5 digit nos that can be formed by using 0, 1, 3, 5, 8.( Repetition is not allowed.)=4*4*3*2*1=96 Total No. of 4 digit or 5 digit nos that can be formed by using 0, 1, 3, 5, 8.( Repetition is not allowed.)=96+96=192
- 13 years agoHelpfull: Yes(3) No(3)
- Two coins are flipped.
One is shown head. So here we already got head. The probability is = 1.
Another one is either head or tail. So probability of getting head is =1/2.
So total probability is =1+1/2
=3/2. - 13 years agoHelpfull: Yes(1) No(9)
- 1st coin 2nd coin
HEAD HEAD
HEAD TAIL
TAIL HEAD
TAIL TAIL
In question given that output is HEAD...so there are only 3 ways,
4th way TAIL-TAIL is not taken
so the P ( BOTH HEADS ) = 1/3 - 9 years agoHelpfull: Yes(1) No(0)
- sample space for two coins are flipped is S = {HH, HT, TH, TT}
one of the output is known to be head therefore new sample space becomes S1 = {HT, HH, TH}
now getting the both heads probability is 1/3 - 9 years agoHelpfull: Yes(1) No(0)
- 1/2, according to the question it is known that one coin should show head but second one is doubt so the probability to show head is for one coin is 1/2, if it happen the two coins shows head
- 9 years agoHelpfull: Yes(0) No(0)
- S={HH,HT,TH,TT}
E={HH}
P(E)=1/4 - 7 years agoHelpfull: Yes(0) No(0)
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