there are 3 temples n river..
location of river n temple is alternatively...
such as..river temple river temple river temple,,
a person having some flowers ,n when that person moves in river the flower got doubled...n person put equal no of flowers in each temple..n at the end no flower is left with him...then how many flowers intially person carried...
n how many flowers he put in ach temple...

• I used backtrack method:-
  Let us take t1-temple1, t2-temple2, t3-temple3, r1-river1, r2-river2, r3-river3 and x is the flowers put in temple.
  He had nothing (zero) flowers after put flowers in t3.
  Before he put flowers in t3 he had x flowers in his hand that is after crossing r3.
  Before crossing r3 he had an only x/2 flower that is after put flowers in t2. Before he put flowers in t2 he had only (x+x/2) =3x/2 flowers in his hand that is after crossing r2.
  Before crossing r2 he had an only 3x/4 flowers that is after put flowers in t1. Before he put flowers in t1 he had only (x+3x/4) =7x/4 flowers in his hand that is after crossing r1.
  Before crossing r1 he had only 7x/8 flowers.
  So definitely x is the multiple of 8.
• 13 years agoHelpfull: Yes(32) No(8)
• From Nishant's solution
  He will carry 7*n flowers initially and keep 8*n flowers at each temple.
  where n can have value 1,2,3.....
• 13 years agoHelpfull: Yes(15) No(4)
• Initially he had 7 flowers and put 8 flowers at each temple.
• 13 years agoHelpfull: Yes(14) No(6)
• He will carry 7*n flowers initially and keep 2*n flowers at each temple.
  where n can have value 1,2,3.....
• 13 years agoHelpfull: Yes(11) No(7)
• 7 flowers intially carreied
  8 flowers has to put in temple
• 13 years agoHelpfull: Yes(8) No(9)
• 7 flowers and he will keep 8 flowers in the temple
• 13 years agoHelpfull: Yes(8) No(8)
• Pls check this qn. How many 4 or 5 digit numbers can be formed by using 0, 1, 3, 5, 8. Repetition is not allowed. None of the given options is correct. No. of 4 digit nos that can be formed by using 0, 1, 3, 5, 8.( Repetition is not allowed.)=4*4*3*2=96 No. of 5 digit nos that can be formed by using 0, 1, 3, 5, 8.( Repetition is not allowed.)=4*4*3*2*1=96 Total No. of 4 digit or 5 digit nos that can be formed by using 0, 1, 3, 5, 8.( Repetition is not allowed.)=96+96=192
• 13 years agoHelpfull: Yes(8) No(4)