If all the 6 are replaced by 9, then the algebraic sum of all the numbers from 1 to 100 (both inclusive) varies by how much?

• unit place increased by 3. So 6,16,26,....96. Total 10*3 = 30 increased.
  ten's place increased by 30. So 60,61,...69. Total 10*30 = 300 increased.
  So total varies = 300 + 30= 330.
• 13 years agoHelpfull: Yes(45) No(4)
• 1-50 -> +15
  51-59 -> +3
  60-70 -> +303(+3 additional for 66)
  71-100 ->+9
  
  Hence, Total 330.
• 13 years agoHelpfull: Yes(7) No(6)
• 6,16,26,36,46,56,76,86,96------> 9*3=27
  60,61,62,63,64,65,67,68,69----> 9*30=270
  66-------------------------------------->33 (because 99-66=33)
  
  so the total change = 27+270+33= 330
• 10 years agoHelpfull: Yes(5) No(1)
• Total 20 6s lies in between 1 to 100,so difference of 60 will be answer i.e 20*3=60
• 13 years agoHelpfull: Yes(1) No(17)
• If all 6 are replaced by 9.. Then from 1 to 10 .. Result increment by 3.. Similarly in 11-20,21-30,Etc... Thus 10*3=30 is the answer..!!!
• 13 years agoHelpfull: Yes(1) No(10)
• 3+3+3+3+3+3+30+33+3+3+3=90
• 13 years agoHelpfull: Yes(0) No(23)