Rs 50000 is divided into two parts One part is given to a person with 10% interest and another part is given to a person with 20 % interest. At the end of first year he gets profit 7000 Find money given by 10%?

• let first parrt is x and second part is y then x+y=50000----------eq1
  total profit=profit on x +profit on y
  7000=(x*10*1)/100 + (y*20*1)/100
  70000=x+2y-----------------------------------eq2
  70000=50000+y
  so y=20000 then x =50000-20000=30000
  first part =30000
• 14 years agoHelpfull: Yes(28) No(3)
• 30,000
  sol. let x was given to a with 10% interest.
  then b got 50,000 - x
  interest = p*t*r /100
  so
  7000 =((50000 - x)*1*20)/100 +(x*1*10)/100
  700000 = 1000000 - 10x
  x = 30000
  
• 14 years agoHelpfull: Yes(6) No(1)
• let the total principle be P=50000
  its divided as
  p1=x
  p2=50000-x
  SI1= (p1*n*r)/100 =(x*10*1)/100 =x/10
  SI2= (p2*n*r)/100 =((50000-x)*20*1)/100 =(100000-2x)/10
  now given,
  SI1+SI2=7000
  x/10 + (100000-2x)/10
  therefore,
  x=30000
  
• 12 years agoHelpfull: Yes(3) No(0)
• 30000
  20% of 20000 = 4000
  10% of 30000 = 3000
  
  4000+3000=7000
• 12 years agoHelpfull: Yes(1) No(6)
• Divide 50000 in 2 part x and (50000-x)
  10% of x=x*(10/100) and 20% of (50000-x)= (50000-x) *(20/100)
  [x*(10/100)]+[(50000-x) *(20/100)]=7000
  so x=30000
  
  
  
• 12 years agoHelpfull: Yes(1) No(0)
• LET 50,000 DIVIDE INTO TWO PARTS THAT IS X AND Y,
  NOW, 10% OF X AND 20% OF Y=7000=((10*X)/100)+((20*Y)/100)---1
  AND X+Y=50,000---2
  AFTER SOLVING THIS 2 EQUATIONS 1 AND 2 WE GET X=30,000 Y=20,000
  NOW AT THE END OF 1 YEAR
  MONEY RETURN BY 10% WILL BE =30000+((30,000*10)/100) THAT IS=33,000
  SO ANSWER IS 33,000
• 11 years agoHelpfull: Yes(1) No(4)