MBA Exam

A dice is rolled three times and sum of three numbers appearing on the uppermost face is 15. The chance that the first roll was a four isOptions:1. 2/52. 1/53. 1/64. None of these

1) 1
2) 2
3) 3
4) 4

Read Solution (Total 1)

There are 3 positions to be filled.
____+ ____ +____ = 15

The possible combinations are
Case 1: (6 6 3)
(6 3 6)
(3 6 6) total 3 combinations

Case 2: (4 5 6)
(4 6 5)
(5 6 4)
(5 4 6)
(6 5 4)
(6 4 5) total 6 combinations

Case 3: (5 5 5) only 1 combination

So probability is possible/total

Possible is 2 because, the question says that uppermost face should show 4, and in case 2 only the 4 appears twice as the uppermost face so it will be 2

Total possibilities would be 6 + 3+ 1 = 10

so probability is 2/10 or 1/5
8 years agoHelpfull: Yes(0) No(0)

MBA Other Question

IF f(0, y) = y+1and f(x+1, y)= f(x, f(x , y) ),Then what is the value of f(1, 2)..??CAT 2000

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A bag contains 2 red, 3 green, 4 blue and 5 white balls. Two balls are drawn at random from the bag without replacement. X is defined as the event that at least one of the two balls drawn is white and Y is defined as the event that none of the two balls drawn is white. Then,A)P(X) = P(Y)B)P(X) < P(Y)C)P(X) > P(Y)D)P(X) = 1.5 Ã— P(Y)

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