MBA
Exam
A dice is rolled three times and sum of three numbers appearing on the uppermost face is 15. The chance that the first roll was a four isOptions:1. 2/52. 1/53. 1/64. None of these 1) 1 2) 2 3) 3 4) 4
Read Solution (Total 1)
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- There are 3 positions to be filled.
____+ ____ +____ = 15
The possible combinations are
Case 1: (6 6 3)
(6 3 6)
(3 6 6) total 3 combinations
Case 2: (4 5 6)
(4 6 5)
(5 6 4)
(5 4 6)
(6 5 4)
(6 4 5) total 6 combinations
Case 3: (5 5 5) only 1 combination
So probability is possible/total
Possible is 2 because, the question says that uppermost face should show 4, and in case 2 only the 4 appears twice as the uppermost face so it will be 2
Total possibilities would be 6 + 3+ 1 = 10
so probability is 2/10 or 1/5 - 7 years agoHelpfull: Yes(0) No(0)
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