A bag contains 2 red, 3 green, 4 blue and 5 white balls. Two balls are drawn at random from the bag without replacement. X is defined as the event that at least one of the two balls drawn is white and Y is defined as the event that none of the two balls drawn is white. Then,A)P(X) = P(Y)B)P(X) < P(Y)C)P(X) > P(Y)D)P(X) = 1.5 × P(Y)

1) 1
2) 2
3) 3
4) 4