HCL
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Numerical Ability
Clocks and Calendars
1/3 of a certain journey is covered at the rate of 25km/hr,1/4 at the rate
of 30 km/hr and the rest is 50 km/hr.the avg speed for the whole journey is :
option: 30,30,33 1/3,37 1/12 km/hr
Read Solution (Total 3)
-
- Let total distance be x.
T=x/3*25+x/4*30+5x/12*50=x/75+x/120+x/120.
Therefore avg.speed=x/9x/300=100/3 - 9 years agoHelpfull: Yes(9) No(4)
- let assume total distance will be 120km then
distance traveled at teh speed 25km/hr=1/3*120=40km the time=40/25=1.6hrs
distance traveled at the speed 30km/hr=1/4*120=30kmthe time is=30/30=1 hr
then remaining distance is 120-40-30=50km
the time taken to travel 50km=50/50=1hr
so total time is=1.6+1+1=3.6 hrs
so avg speed =120/3.6=33.33km/hr - 9 years agoHelpfull: Yes(4) No(2)
- ans-> 33.33kmph
avg speed= total dist / total time
total distance= d(say)
total time= d/(3*25) + d/(4*30) + 5d/(12*50)
putting the values in above formula
we get avg speed as 33.33kmph - 8 years agoHelpfull: Yes(1) No(1)
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