if 2p/(p^2-2p+1) =1/4 ,p!=0,then the value of p+1/p is:
option: 4,5,10,12

• P^2-2p+1=8p given
  
  
  P+(1/p)=(p^2+1)/p=(p^2+1+2p-2p)/p
  =10p/p=10.
  Ans:10
• 9 years agoHelpfull: Yes(15) No(1)
• 8p=(p^2-2p+1)
  8p=p^2(1-2/p+1/p^2)
  8=p(1-2/p+1/p^2)
  8=p-2+1/p
  10=p+1/p
  so Ans=10
• 9 years agoHelpfull: Yes(5) No(0)
• 8p=(p-1)^2
  8=p(1-1/p)^2
  8=p-2+1/P then p+1/p=10
• 9 years agoHelpfull: Yes(2) No(0)
• 2p/p^2-2p+1=1/4
  by taking p common,
  2p/p(p-2+1/p)=1/4
  cancelling p we get,
  2/p-2+1/p=1/4
  8=p-2+1/p then
  8+2=p+1/p
  10=p+1/p
  so answer is 10
• 7 years agoHelpfull: Yes(1) No(0)
• 10
  p=10-96^0.5
  (p+1/p)^2=p^2+(1/p)^2+2=100
  p+1/p=10
  
• 9 years agoHelpfull: Yes(0) No(0)