if a ractanlgle area is equal to 2*area of a circle
(radius r) if rectangle is inscribed in a circle so what will be the perimeter of rectangle

• Impossible question...
  rectangle is inscribed in a circle and ractanlgle area is equal to 2*area of a circle.
  how could it be?
  
• 9 years agoHelpfull: Yes(28) No(1)
• 4r*sqrt(1+pi)
  
• 9 years agoHelpfull: Yes(4) No(4)
• let L=length of rectangle
  B=height of rectangle
  r= radius of circle
  now given => L*B= 2*(pi*R*R).........................(1)
  
  when rectangle is inscribed in circle (Draw to paper), we will get that
  => R^2= (L/2)^2 + (B/2)^2..............................(using pythogoras theorem)
  => (R*R)= (L*L)/4 +(B*B)/4
  => (R*R)*4 =(L*L) +(B*B)................................(2)
  
  we have to find 2*(L+B) = 2*sqrt[ (L+B)^2]
  => 2*sqrt[(L*L)+(B*B)+2*L*B]............................ using (a+b)^2 = a^2 +b^2 +2*a*b formula
  now use equ. (1) and (2)
  
  => 2* sqrt[4*(R*R)+ 2*(2*pi*R*R)]
  => 2*2*R*sqrt [1+pi]................................... here we taken common 4*R*R from sqrt
  => 4*R * sqrt[1+pi].. !!!!!!!!!!!!!!!!!!!!!!!!!!!!! :)
  
  
• 9 years agoHelpfull: Yes(4) No(3)
• Ans : sqrt(8pi+8)*r
  sol : r= sqrt(l*l + b*b) / 2
  
  2*pi*r*r = l*b
  put the value of r in above equation ... and by solving we get : 2(l+b) = sqrt(l*l+b*b) *r
• 9 years agoHelpfull: Yes(1) No(1)
• @Ramdas is a legend . He can answer to wrong question also.
• 2 years agoHelpfull: Yes(0) No(0)