if there are x number of students in class such that x<=100 .there are 16% students whose age
is greater than 6 yrs and remaining students are less than 6 yrs,the avg marks scored by all students is 80 and avg marks scored by less than 6 yrs students is 88 then calculate the avg marks scored by students of age greater than 6 yrs.

• no. of students of age greater than 6 = .16x
  no. of students of age less than 6 = .84x
  
  let avg marks scored by students of age greater than 6 yr is = y then
  
  .84x * 88 + .16x * y = 80*x
  => 73.92 + .16y = 80
  => y = 38
• 9 years agoHelpfull: Yes(33) No(0)
• 16% student of total student =16/100*100=16
  so remaining students=100-16=84
  avg marks scored by all students= 100*80=8000
  avg marks scored by less than 6 yrs student=84*88=7392
  so avg marks scored by students of age greater than 6 yrs=(8000-7392)/16=608/16= 38
  So The ans is 38
• 9 years agoHelpfull: Yes(4) No(0)
• ans:- 38
  ((88*88)+(X*16))/100 = 80
  so, X = 38
• 9 years agoHelpfull: Yes(0) No(0)
• by allegations
  6years
  88(avg) x
  80(over-all-avg)
  74 : 16 (contribution)
  >>now solve the equations as:
  80-x/8=21/4
  320-4x=168
  x=38
  
• 9 years agoHelpfull: Yes(0) No(0)
• let's take x as 100 16%= 16 student age is greater than 6 years
  remaining student are 84 who's age is less than 6 years
  avg marks of all all student is 80 (80*100)=8000
  avg marks scored by less than 6 years student is (84*88)=7392 than 8000-7392=608
  608/16=38 so 38 is the answer
• 9 years agoHelpfull: Yes(0) No(0)