in a normal 5 day work week,each of two employees

• Correct Question: In a normal 5-day work week, each of 12 employees produces 300 items per day-last week, 1/3 of the employees were absent from work for 2/5 of the days in the week. how many total items were produced last week?
  Option
  a) 18000
  b) 14400
  c) 6000
  d) 15600
  e) 16,200
  
  Solution:15600 items
  
  1 employee produces 300 items per day
  
  1/3 of the employees were absent for 2/5 days of last week.
  ==> 4 employees were absent for 2 days.
  
  Items produced by them in 3 days
  = 300*3*4
  =3600
  
  Items produced by other employees
  =8*5*300
  =12000
  
  Total items produced = 12000+3600
  =15600
  
• 9 years agoHelpfull: Yes(11) No(0)
• 12*5*300=18000
  absence=2/5*1/3=2/15
  so presence=13/15
  totql item produced=13/15*18000=15600
  
• 9 years agoHelpfull: Yes(6) No(0)
• In a normal 5-day work week, each of 12 employees produces 300 items per day-last week, 1/3 of the employees were absent from work for 2/5 of the days in the week. how many total items were produced last week?
  Option
  a) 18000
  b) 14400
  c) 6000
  d) 15600
  e) 16,200
  answer : c 15600
• 9 years agoHelpfull: Yes(1) No(1)
• 15600 is correct.
• 8 years agoHelpfull: Yes(1) No(0)
• no. of items produced by each employee per day = 300/12= 25
  last week 1/3 of the employees were absent for 2/5 of the week .. means that for first 2 days only 8 employees worked instead of 12 ..
  day 1 ( 8 employee ) = 8*25 = 200
  day 2 ( 8 employee ) =8*25=200
  day 3 (12 employee )=12*25=300
  day 4 (12 employee )=12*25=300
  day 5 (12 employee)=12*25=300
  
  
  so total 1,300items
• 9 years agoHelpfull: Yes(0) No(4)