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Numerical Ability
Averages
The average age of a husband and his wife was 23 years at the time of their marriage. After five years they have a one year old child. What is the average age of the family ?
Option
1) 21 years
2) 20 years
3) 18 years
4) 19 years
Read Solution (Total 10)
-
- after 5 years the average age of the two will be 28.
now the child is one year old ,
total age = 28*2 + 1 = 57
average age = total age/family members(3)
=> 57/3 = 19 - 9 years agoHelpfull: Yes(22) No(2)
- given average =23
therefore total age = 23 *2=46
after 5 years total age of father and mom =56
they have 1yr old child at 5th year .. therefore total age is 57
hence average age of family is 57/3 = 19yrs - 9 years agoHelpfull: Yes(7) No(0)
- wife=23,fathar=23;
after 5 year=>(23+5)+(23+5)+1=>57/3=>19 - 9 years agoHelpfull: Yes(4) No(1)
- 3->(23*2+5*1)+1
- 9 years agoHelpfull: Yes(0) No(0)
- 4)19 years
- 9 years agoHelpfull: Yes(0) No(0)
- 4=23+5/2+1
- 9 years agoHelpfull: Yes(0) No(0)
- let X and Y be ages of husband and wife
At the time of marriage average of their ages{X+Y}/2=23 ==>X+Y=46---(1)
after 5yrs they have 1 yr old child
[(X+5)+(Y+5)+1]/3=[X+Y+11]/3---(2)
substitute 1 in 2
(46+11)/3=19yrs is average age of the family - 9 years agoHelpfull: Yes(0) No(0)
- Ans:19
Consider current age of husband & wife as 28, child's age is 1 ,
total of age is 28+28+1=57, average is 57/3=19. - 9 years agoHelpfull: Yes(0) No(0)
- Avg= (H+W)/2
(H+W) = 23*2 = 46
After 5 yrs (H+5) & (W+5)
(H+W) = 56
Avg = (H+W+Child) / 3
56+1 / 3
19 yrs
- 9 years agoHelpfull: Yes(0) No(0)
- let H=husband's age
W=wife's age
(H+W)/2=23
So, H+W=46
after 5 years
C(child age)=1 year
So
average age after 5 years AVG =(H+5+W+5+1)/3
=(H+W+11)/3
we know H+W=46
So
average age after 5 years AVG =(46+11)/3=19
so answer is 19 - 7 years agoHelpfull: Yes(0) No(0)
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