A batsman makes a score of 87 runs in the 17th inning and thus increases his averages by 3 What

let the average after 17th inning =x
Then average after 16th inning=(x-3)
Therefore 16(x-3)+87=17x
Therefore x=39
9 years agoHelpfull: Yes(6) No(1)
let average after 16th over = x
let average after 17th over = x+3
hence
16x+87=17(x+3)
16x+87=17x+51
x=36
hence
average after 16th over = x=36
average after 16th over = x+3=36+3=39
9 years agoHelpfull: Yes(1) No(0)
AVG16 = Sum16 / 16
X* 16 = sum16 ... ..... (1)

AVG17 = (sum16 + 87)/17
(x+3)*17 = sum16
(X + 3)*17 = sum16 + 87
17X + 51 - 87 = sum16
x = 36

avg17 = 39
9 years agoHelpfull: Yes(0) No(0)
let the batsman score 'r' runs in his 16th inning and his average in the 16th inning is found that it is 'x'
by this we write
r/16=x
r=16*x
then at the 17th inning
( r+87)/17=x+3
let put the value of r=16*x to the above equation
(16*x+87)/17=x+3
by solving this we get value of x=36
so the average after 17th inning would be x+3=39
9 years agoHelpfull: Yes(0) No(0)
Let his score till 16th innings be x. In 17th innings he scores 87 which leads to an increase in its average.
Earlier average(till 16th inning)= score till 16th inning/no. of innings-----> x/16. After 17th inning Average becomes "New Score"/17-----> x+87/17. As given in the question,difference of average is 3,so, {(x+87)/17}-(x/16)=3... this gives old score=x. So,now the new avg= 576+87/17... which is 39
9 years agoHelpfull: Yes(0) No(0)

A batsman makes a score of 87 runs in the 17th inning and thus increases his averages by 3. What is his average after 17th inning?

Option
1) 39
2) 35
3) 42
4) 40.5