Elitmus
Exam
Numerical Ability
Sequence and Series
if the sum of 2000 consecutive integer is 5000 then what will be the sum of each digit for last term.
option:
A-4
B-3
C-5
D-none of these
Read Solution (Total 8)
-
- Sn=n/2{2a+(n-1)d}
Sum is 5000 of 2000 consecutive integers.
so, d= 1 (since nos are consecutive), n=2000, Sn =5000
5000=2000/2{2a+(2000-1)*1}
solving, a= -997
NOW,
apply Sn=n/2(a+l)
5000=2000/2(-997+l)
l=1002 (last term)
so summation is 1+0+0+2= 3
--option B- 3 - 9 years agoHelpfull: Yes(66) No(0)
- I AM PROUD OF @KUMAR AVINASH
- 9 years agoHelpfull: Yes(5) No(2)
- 2502 last term. ans 9 i.e D
- 9 years agoHelpfull: Yes(1) No(8)
- jiyo chacha tum to hila diye!!
- 9 years agoHelpfull: Yes(1) No(1)
- 3 last term will be 1002
- 9 years agoHelpfull: Yes(0) No(5)
- n=2000; sn=5000
n/2(2*a+(n-1)*d)=5000
solving a=-997
t2000=1002
ans=3
- 9 years agoHelpfull: Yes(0) No(0)
- 1000(2*a+1999)=5000 (d=1)
from above a=-997 which is 1st term
now, -997+1999=an
an=1002
sum of digit of 1002 is 3 - 9 years agoHelpfull: Yes(0) No(0)
- chatur right.........
- 7 years agoHelpfull: Yes(0) No(1)
Elitmus Other Question
A set B={2,3,5,6,7,10,_ ,_ ,_______} contain 300 no. in which square and cube of the no. are eliminated. then what will be the last number of the set B.
P, Q and R can do a work in 20, 30 and 60 days respectively. How many days does it need to complete the work if P does the work and he is assisted by Q and R on every third day?
Options
1) 10 days
2) 14 days
3) 15 days
4) 9 days