An internet recently hired 8 new network,in addvertisement 20 network already employed.All new network cam from university A.In addition 75%of computer addvertisement came from same university A.what fraction of original 20 network addvertisement came from same univerity A? pls help to solve

• Answer is : 13/20
  
  Explanation :
  New networks= 8
  Already employed networks= 20
  Total networks= 28
  
  computer advt. from uni.A= 28*(75/100) =21
  out 28 networks 21 came from uni.A
  among these 21 we know 8 are newly hired
  so 21-8=13 networks among previously employed networks came from uni.A
  
  Answer is : 13/20
• 9 years agoHelpfull: Yes(48) No(0)
• employee A woks fom 0100 to 0845 (24 h clock) on each 5 days this week.Next week he is scheduled to work the same total hours but will work a compressed 4 day wok schedule.If he starts work at 0100 next week what time will he finish each day? plz give the answer
• 9 years agoHelpfull: Yes(11) No(2)
• total networks :old networks+new networks
  =20+8=28
  so 75% of the addition of computer advertisement = 28*(75/100)=21
  
  out of 28 networks 21 from same university A
  
  so old network =21-8=13
  
  Answer: 13/20
• 8 years agoHelpfull: Yes(3) No(0)
• An internet recently hired 8
  20 network already employed.
  20+8=28
  In addition 75%of computer addvertisement came from same university A
  28*(75/100)=21
  out of 20 network 21 computer advati unit of a
  28-21=13
  answer is:13/20;
• 7 years agoHelpfull: Yes(1) No(0)
• i think 21 is the correct answer
• 9 years agoHelpfull: Yes(0) No(8)