IBM
Company
Numerical Ability
Profit and Loss
A shop keeper sell an article gets profit of 20% had he bought it for 20% less and sold it for Rs 120 less he would have still bought profit of 20% what is the cost price of article
Read Solution (Total 10)
-
- let c.p be x,
1st s.p =(120/100)x=6x/5
2nd s.p=(80/100)x=4x/5
filnal profit 20% so
120/100 * 4x/5
120 rs less so
6x/5 - 24x/25 =120
x=500
- 9 years agoHelpfull: Yes(16) No(2)
- let cost price=x; selling price=120%(x)
new cost price=80%(x) i,e 20% less than previous cost price
new selling price= 120%(x)-120 therefore from the question
but new selling price = 120%(80%x) therefore from cost price
120%(80%(x))=120%(x)-120
x=500
- 9 years agoHelpfull: Yes(10) No(0)
- @ARUNA
What is the value of 120% of x once check...
120% of x is 6/5 - 9 years agoHelpfull: Yes(6) No(2)
- LET CP=X
120% of x = 5x/4
80% of x= 4x / 5
120% of 4x/5= 24x/5
5x/4 - 24x/25 = rs120
cp=RS 500 - 9 years agoHelpfull: Yes(5) No(13)
- ans =500
120% of x=6x/5
80% of x=4x/5
120% of 4x/5=24x/25
6x/5 - 24x/25=120
6x=3000
x=500
- 9 years agoHelpfull: Yes(2) No(0)
- can anyone plz provide the solution for 21,24,25 in detail??
- 9 years agoHelpfull: Yes(1) No(1)
- sp1=1.20cp1
cp2=0.80cp1
sp2=sp1-120
sp2=1.20cp2
thn solving all
sp1-120=1.20(0.80cp1)
cp1=500 - 9 years agoHelpfull: Yes(0) No(1)
- LET cp = X
cp sp
case1: X 1.2X (when profit 20%)
case2: 0.8x 1.2x-120 (when sp is less than 120 )
(sp-cp)/cp = 20/100 (profit %)----------(1)
put value of sp and cp in equation (1)
x = 500 - 8 years agoHelpfull: Yes(0) No(0)
- ans=x=500
let cost prize in 1st case =x
then sell it to get profit 20% then
sp1=x+x*20%=(6x/5)
next statement says that he bought 20% less means that
new cost prize=80% of that x ;
and still get profit so sp=new cp*120/100
sp2=80x/100 *120/100
sp2=24x/25
a/c 120 less means sp1-sp2=120
6x/5-24x/25=120
x=500 ans - 8 years agoHelpfull: Yes(0) No(1)
- A item sold=17/36
A item remain=1-17/36=19/36
A item buy back=2/36
total of A item=19/36+2/36=21/36
the item B sold=15/84
item remain=1-15/84=(84-15)/84=69/84
item C sold=3/504
item C remain=1-3/504=(504-3)/504=501/504
fractions A,B,C =21/36 + 69/84 + 501/504 = (1209/504) - 8 years agoHelpfull: Yes(0) No(0)
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