We have to find the possible combination to get the sum as 7. As for example 1+1+1+4 = 7. or 2+2+1+2 = 7.

How many combinations are possible ?

• total 14
  1+1+1+1+1+1+1+1=7
  2+1+1+1+1+1=7
  3+1+1+1+1=7
  4+1+1+1=7
  5+1+1=7
  6+1=7
  2+2+2+1=7
  2+2+1+1+1=7
  3+3+1=7
  3+2+1=7
  4+3=7
  4+2+1=7
  5+2=7
  3+2+2=7
  
• 9 years agoHelpfull: Yes(8) No(6)
• Ans: 20
  1+1+1+4-----> 4!/3!=4
  1+1+2+3------>4!/2!=12
  1+2+2+2------->4!/3!=4
  
  So, 4+12+4=20
• 9 years agoHelpfull: Yes(7) No(2)
• a+b+c+d=7 i.e whole no. sol of this equation..so the sol will be 10c3 which is equal to 120
• 9 years agoHelpfull: Yes(2) No(1)
• Here we are taking only natural number a+b+c+D=7
  Partition is 3 and we need to discard zero so a+b+c+D=4
  And partition is 3 so ans will be 7C3
  If it is whole no then ans will be 10C3
• 9 years agoHelpfull: Yes(1) No(0)
• 1+1+1+4=4 c
  2+2+1+2=4 c
  1+2+3+1=12 c(4!/2! since 1 is repeated twice)
  3+1+3=3 c
  5+1+1=3 c
  2+2+3=3 c
  4+1+2=6c(3!)
  5+2=2 c
  6+1=2c,3+4=2c=41 combinatios possible
• 9 years agoHelpfull: Yes(0) No(3)
• answer is 84.
  
• 9 years agoHelpfull: Yes(0) No(3)
• 13 is the answer.
  
• 9 years agoHelpfull: Yes(0) No(1)
• according to me answer is 33
• 8 years agoHelpfull: Yes(0) No(0)