Given a 3 digit number. for example 343 and the multiplication of the digits will give 36. as for example 3*4*3 = 36.

This way how many possible three digit numbers can be formed ??

• find prime factors of 36 first=>3^2,2^2
  941=3! ways-6
  661=3!/2! ways-3
  632=3! ways-6
  334=3!/2! ways-3
  229=3!/2! ways-3
  total 21 ways
  we can use permutation and combinations to arrive at solution easily
• 9 years agoHelpfull: Yes(20) No(1)
• 941=3! ways-6
  632=3! ways-6
  661=3!/2! ways-3
  334=3!/2! ways-3
  229=3!/2! ways-3
  total 21 ways
  this is rigth answer :)
  
• 9 years agoHelpfull: Yes(4) No(0)
• find prime factors of 36 first=>3,4,3
  941=3! ways-6
  661=3!/2! ways-3
  632=3! ways-6
  334=3!/2! ways-3
  
  total 18 ways
• 9 years agoHelpfull: Yes(1) No(3)
• ans: 12
  Solution: factors of 36 is 3,3,2,2
  So by these we can form 3 digits no. such as- 362,922,334
  so by arranging the digits we can get 3!+3+3= 12 such nos.
• 9 years agoHelpfull: Yes(1) No(0)
• 491=3!
  326=3!
  263=3!
  292=3!/2!
  343=3!/2!
  661=3!/2!
  so total is 25
  
• 9 years agoHelpfull: Yes(0) No(2)