Elitmus
Exam
Numerical Ability
Sequence and Series
The difference between two numbers is 48 and the difference between the arithmetic mean and the geometric mean is two more than half of 1/3 of 96.Find the numbers.
(a)49,1 (b)12,60 (c)36,84 (d)none of these
Read Solution (Total 4)
-
- let two no be a and b
airthemetic mean= a+b/2
geometric mean = sqrt(ab)
by question, a-b=48-----------------------------1
(a+b)/2 - sqrt(ab)= 18
==> a+b - 2sqrt(ab)=36
==> a+b= 36+ 2sqrt(ab)------------------------2
by equation 1 and 2
2a = 84+ 2sqrt(ab)
so, a-sqrt(ab) =42
now check the option,
option a is satisfied the equation .........49-sqrt(49*1)= 42
so ans will be 49,1 - 9 years agoHelpfull: Yes(17) No(0)
- according to the question
airthmetic mean-geometric mean=2+1/2*1/3*96
(49+1)/2-sqrt(49*1)=2+16
18=18
so a is the ans 49,1 - 9 years agoHelpfull: Yes(4) No(0)
- ans: 49,1
description: x-y=48
arithmetic mean - geometric mean =2 more than the half of 1/3 of 96
=> (x+y)/2 - sqrt(xy) = 2 * (1/2) *(1/3)*96
(49+1)/2 - sqrt(49) = 18
18 = 18 - 9 years agoHelpfull: Yes(0) No(2)
- ans: (A) 49,1
Solution: Jst go through the options ;)
- 9 years agoHelpfull: Yes(0) No(0)
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