Sum of two number is 1000 and the sum of their recipocal is 2/255.Let the smallest of 2 number be L, so which of the following is correct value range for L?
a)0

• As per the question , let the smaller number be L and larger number be H.
  So, L+H = 1000..........eqn 1
  And
  1/L+1/H= 2/255
  (L+H)/LH = 2/255
  LH = (L+H)*255/2
  LH= 127500.................eqn 2
  Now,
  (H-L)^2 =(H+L)^2 - 4HL
  (H-L)^2 = 1000000-4*127500
  = 1000000-510000
  =490000
  Now,
  (H-L) =sqrt(490000)
  = 700
  H-L=700...............................eqn 3
  From eqn 1 and 3
  L=150
  H=850
  
• 9 years agoHelpfull: Yes(17) No(0)
• Ans =150
  the process used is same as explained in other solution.
• 9 years agoHelpfull: Yes(2) No(0)
• 17
• 9 years agoHelpfull: Yes(1) No(2)
• on solving quadratic equation y^2-1000y+127500
  we get two roots 150 and 850
  smaller one is 150.
• 9 years agoHelpfull: Yes(1) No(0)
• Ans should be = 75
  x+y=1000 so, y=1000-x
  1/x + 1/y = 2/255
  now replace 1/y with 1/(1000-x), and solve ::::
  
  Lastly we get using discriminant method x= 1000 + or - sqt{(1000^2) -4*127500}
  on solving we have to take minimum value so we'll use - not +
  so small number will be 75.
  
  So ans=75
• 9 years agoHelpfull: Yes(0) No(2)
• as per today's eLitmus exam 19/07/2015 options are
  (1) 0
• 9 years agoHelpfull: Yes(0) No(0)