A right angled cone has its height 'h'. The cone is being cut parallel to its base at h/5 distance from its vertex. What will be the ratio of the cone and the cutting portion
Option: 1:24, 1:125, 1:25, not remember

• volume of smaller cone / (volume of bigger cone - volume of smaller cone)
  also by similarity r/R = h/H
  => r/R=1/5
  
  Substituting and solving we get 1/124 ans :)
• 8 years agoHelpfull: Yes(15) No(4)
• let radius of smaller cone=R
  radius of bigger cone=r
  height of smaller cone=h/5
  height of bigger cone=h
  volume of smaller cone=1/3*pi*R^2*h
  volume of reamaining portion=volume of bigger cone - volume of smaller cone
  i.e 1/3*pi*r^2h-1/3*pi*R^2(h/5)
  from the similarity of triangle
  r/R=5:1
  equating value
  we get 1:124
  
• 8 years agoHelpfull: Yes(7) No(1)
• the formula of cone is 1/3 * pi* sqr(r) * h
  as the new cone's height will be h/5 so the volume will be 1/5( 1/3 * pi* sqr(r) * h)
  =1/5(original cone)
  so ans is 1:5
• 8 years agoHelpfull: Yes(3) No(9)
• 1:124 is answer . we use triangle similarity rule by which r/R=h/5/h=h/5h
  now ratio of volume of smaller to cutiing portion (1/3*pi*(h/5)^2*h/5) / (1/3*pi(h*h^2-(h/5)^2*h/5)
  by solving this we get 1/124
• 8 years agoHelpfull: Yes(3) No(1)
• volume of cone=3.14*r*r*h/3, here after cutting the hight =h/5, height of frustm=h-h/5=4h/5, ratio of volume=1:125
• 8 years agoHelpfull: Yes(1) No(4)