Elitmus
Exam
Numerical Ability
Permutation and Combination
There is a circular table. It has 60 chairs. Drakula came and sit on a chair beside another person. What is the minimum no. of person will be so, that wherever he sits he always gets to sit beside a person
Options: 30, 20, 15, 10(not sure)
Read Solution (Total 11)
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- Ans : 20
Exp: Think from basics..
if total seats N = 5 in a circular arrangement ( _ _ M _ _ M ) where first ( _ ) is connected with last Man(M), then min no of persons required= 2.
similarly If N = 9, Man required = 3 i.e,( _ _ M _ _ M _ _ M )
If N= 12, Man required = 4 i.e, ( _ _ M _ _ M _ _ M _ _ M)
have u got any relation??
the no of man required is = Total no of seats in circle / 3
So, A/Q total seat = 60. Man required = 60/3=20 Ans. - 9 years agoHelpfull: Yes(31) No(0)
- 20 will be the ans
the max gap diff between 2 person allowed is 2.
so if you stretch the round table into a line the figure will look like _ _ man _ _ man _ _ man _ _ man...
so its clear that in each 3 seats there will be one man so ans will be 60/3=20 - 9 years agoHelpfull: Yes(9) No(3)
- you need imagination .. just put one man at no.1 than give a gap of twoand put a man at 4 again like man _ _ man_ _man......make it circle and count you will get 20
- 9 years agoHelpfull: Yes(2) No(1)
- Vishal please let me know Why are you imagining gap of two persons between two?
- 9 years agoHelpfull: Yes(1) No(0)
- ans 29 i think
- 9 years agoHelpfull: Yes(0) No(2)
- The ans will be 19.
- 9 years agoHelpfull: Yes(0) No(1)
- The ans will be 19.
- 9 years agoHelpfull: Yes(0) No(0)
- The ans will be 19.
- 9 years agoHelpfull: Yes(0) No(1)
- The ans will be 19.
- 9 years agoHelpfull: Yes(0) No(0)
- 15 you can check in google
- 9 years agoHelpfull: Yes(0) No(0)
- 20...if gap betn evry seat is 2 thn Drakula can bite one on left or r8 bt nt both...
- 9 years agoHelpfull: Yes(0) No(0)
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