Elitmus
Exam
Numerical Ability
Number System
How many numbers in the set X if it has only odd number between 100 and 300 and divisible by 3........?
Read Solution (Total 21)
-
- the series is- 105,111,117------------297
here
a=105, d=6,
as Tn=a+(n-1)d
so,
297=105+(n-1)6
=>n-1=32
so, n=33
ANS=33 - 9 years agoHelpfull: Yes(36) No(9)
- the series is:105,111.........297
a=105,d=6,tn=297
tn=a+(n-1)d
297=105+(n-1)6
n=33. - 9 years agoHelpfull: Yes(7) No(3)
- Ans:33
- 9 years agoHelpfull: Yes(3) No(0)
- the series would be 102,105.......297
297=102+(n-1)3 =>
n=66
ANS- 66 - 9 years agoHelpfull: Yes(2) No(18)
- 105, 111.......,297
297=105+(n-1)6
n= 33 - 9 years agoHelpfull: Yes(2) No(2)
- the series would be 102, 105,108 and so on the last being 300 so no of terms wouldbe (300-102/3)+1 (Last term -first term/common difference)+1 and so the answer is 67
- 9 years agoHelpfull: Yes(2) No(2)
- The Series Starts From 102 And Ends At 300.
So, Tn = a + (n-1)*d
Tn=300, a= 102, d= 3
300 = 102 + (n-1)*3
=> (n-1) = (300 - 102)/3 = 66
=> n=66 +1 = 67
Hence, n= 67 ::::::::::::::::: :) - 9 years agoHelpfull: Yes(2) No(2)
- Sorry, My Mistake ---- Answer Is 33 = 67/2 (For Odd And Even)... So Odd = 33 And Even = 34...::::::: :)
- 9 years agoHelpfull: Yes(2) No(0)
- If both 100 and 300 included then answer would be 67 terms....
- 9 years agoHelpfull: Yes(1) No(6)
- 33 becoz i am saying
- 9 years agoHelpfull: Yes(1) No(0)
- Dude !! Question Is To Find Odd numbers So Ans is [67/2] = 33
- 9 years agoHelpfull: Yes(1) No(0)
- 8 numbers will be there
111,117,135,153,159,171.177,195, - 9 years agoHelpfull: Yes(1) No(0)
- first number=105 last=297 diff=6
total no=last-first/diff+1
33 - 9 years agoHelpfull: Yes(1) No(0)
- term=105,111,117............,297
no. of term=297-105/6=32+1=33 - 9 years agoHelpfull: Yes(1) No(0)
- no. of odd terms b/w 100 to 300 =100
105,107,.......297;
l=a+(n-1)d; =>n=33
- 9 years agoHelpfull: Yes(0) No(0)
- answer is 34
- 9 years agoHelpfull: Yes(0) No(0)
- the answer is 67 since 300 is also included
- 9 years agoHelpfull: Yes(0) No(0)
- The first odd no b/w 100-300 is 105 it divisible by 3. the serise is - 105,111,117.........upto 297.so
first term=105 last term=297 and d=6 (d is the difference between terms of the arithmetic progression)
(last term) - (first term)/difference 1.
now, (297-105)/6+1 =>34+1=35 is ans - 9 years agoHelpfull: Yes(0) No(1)
- series like start is 105,111,117,...........297..(1)
not start 102,105 bcz it is also divisible by 6
so now equation 1 behaves like A.P.
we know that
tn=a+(n-1)d
297=105+(n-1)6
n=33 . is the correct answer.
- 8 years agoHelpfull: Yes(0) No(0)
- correct answer is 33
EXPLANATION:
x={105,111,117,...............297} it all number is divisible by 3
accn to arithmetic progression
a=105 ,d =6, tn =297
we know that
tn = a+(n-1)d
297=105+(n-1)6
192=(n-1)6
32=n-1
n=33 - 8 years agoHelpfull: Yes(0) No(0)
- No. divided by 3 between are (102,105,108,111,114,117,........... , 297, 300)
but we need only odd numers.
so,
the series is:105,111.........297
a=105,d=6,last number(l)=297
l=a+(n-1)d
297=105+(n-1)6
n=33 answer - 2 years agoHelpfull: Yes(0) No(0)
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