Elitmus
Exam
Logical Reasoning
Mathematical Reasoning
A women sells 3 different size(in kgs) packs of sugar which are multiples of 1.A person who buys sugar should buy all types of packs.4 different people buys 20,21,23,29 kgs .
what will the maximum and minimum amounts a person can buy??
Read Solution (Total 7)
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- packet are 11,6 and 7
7+7+6=20
7+7+7=21
6+6+11=23
7+11+11=29
and min 6+6+6=18
and max 11+11+11=33 - 9 years agoHelpfull: Yes(10) No(3)
- ans is minimum 2kg pcg maximum 5kg pcg
2kg, 3kg ,5kg pcgs now
a person can pcgs for 20 kg as
2 2kg = 4 kg
2 3kg =6kg
2 5kg =10kg
so total 20 kg.
so for 21 1(2kg) 3(3kg) 2(5kg) which makes 2 9 10 total 21kg
so do all
ans is minimum 2kg pcg maximum 5kg pcg
- 9 years agoHelpfull: Yes(3) No(0)
- Question seems to be inappropriate..............please check...
- 9 years agoHelpfull: Yes(2) No(0)
- data insufficient
- 9 years agoHelpfull: Yes(0) No(0)
- Packets are 2, 7, 11
11+7+2 = 20
7+7+7 = 21
11+11+2=23
11+11+7=29
therefore,
min 2+2+2=6
max 11+11+11=33 - 9 years agoHelpfull: Yes(0) No(7)
- person should buy all type of pack , so q. is wrong
- 8 years agoHelpfull: Yes(0) No(0)
- A person who buys sugar should buy all types of packs.?
This makes a conflicting situation, otherwise there could be more than one solution. - 7 years agoHelpfull: Yes(0) No(0)
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