A lady bought five books namely A,B,C,D,E to distribute her 3 child. How many ways she can distribute books?

• 3^5
  3*3*3*3*3
• 9 years agoHelpfull: Yes(32) No(5)
• 60
  
  With AB there can be 3 possible combinations ABC, ABD or ABE, so similar 3 combinations are possible with AC, AD and AE, total 3*4=12
  Similarly 12 combinations are possible for B, C, D, or E
  So total combinations of 3 with Given A,B,C,D,E=5*12=60
• 9 years agoHelpfull: Yes(21) No(28)
• There are 3 children.The first one can get any of the 5 books,the second can get any one of the remaining four books and the third one any of the remaining 3 books.
  So the total no of ways is 5*4*3=60.
• 9 years agoHelpfull: Yes(15) No(4)
• 3^5.
  because no of filling 3 blank spaces with 5 objects is 3^5
• 9 years agoHelpfull: Yes(8) No(3)
• Since we have to select any 3 books from 5 books, so here we will use Combination.
  5C3(Selecting combination) *3!(Shuffling in selected combination)
  
  so here comes, 5*4*3=60 //Ans.
• 9 years agoHelpfull: Yes(6) No(0)
• ways to distribute 5 objects to 1 child=3
  ways to distribute 5 objects to 2 children=(1,4)+(2,3)=30+60=90
  ways to distribute 5 objects to 3 children=(1,1,3)+(1,2,2)=60+90=150
  hence total=3+90+150=243
• 9 years agoHelpfull: Yes(5) No(9)
• REALLY PUZZLED !!!!!!!!! HOW DEVENDRA MARGHADE GOT BEST SOLUTION........... 110% WRONG
  
  
  
  
• 9 years agoHelpfull: Yes(5) No(9)
• if you want to have pure logicc though that will take a big space in your copy :P..so here how it goes..with the letter 'A' all possible combination to the three kids.ABC,ABD,ABE,ACB,ACD,ACE,ADB,ADC,ADE,AEB,AEC,AED ..COUNT how many ways formed here.i.e 12 ways.so this will multiply by 5 .hence 60.multiply by 5 as for the alphabets A,B,C,D,E.
• 9 years agoHelpfull: Yes(5) No(6)
• i dnt knw y ppl submit their solution mere by guessing. its quite shameful. its helping site fr d aspirants. if u dnt knw den plz dnt commnt illogical answers.
• 9 years agoHelpfull: Yes(5) No(0)
• 3^5.
  Because 5 books is distributed to her 3 child.
• 9 years agoHelpfull: Yes(2) No(2)
• Ans. 3^5
  The lady can distribute the 1st. book to children in 3 ways since there is no any condition so again she can distribute 2nd book in 3 ways in this way the lady can distribute all books in 3^5 ways.
• 9 years agoHelpfull: Yes(2) No(1)
• arpit no 2 books are left all r distributed ...in 5c3
• 9 years agoHelpfull: Yes(2) No(1)
• according to arun sharma
  it will be 3^5
  
  
• 9 years agoHelpfull: Yes(2) No(1)
• Options are1) 60
  2) 168
  3)125
  4)343
  I thought Devendra solution is right
• 9 years agoHelpfull: Yes(1) No(0)
• ans :
  3^5
• 9 years agoHelpfull: Yes(1) No(2)
• 5c3*3! because we have to select 3 things from five and then and the we have to check possible arrangement.
• 9 years agoHelpfull: Yes(1) No(0)
• lady can give 5 books to 1st child, 4 to 2nd child, 3 books to 3rd child. so no of ways will be = 5*4*3
  =60
• 9 years agoHelpfull: Yes(1) No(0)
• Here is 5 types of books A,B,C,D,E.
  distributed in 3 children
  5c3*3!=
  {(5*4*3!)/2!*3!}*3!=60
• 9 years agoHelpfull: Yes(1) No(0)
• _____ _____ _____
  5 4 3
  since no repeation can be so
  
  first place will 5 chances and second place will get 4 (bcz any of one is used so 5-1) same for next (only 3 bcz 4-1)
  
  5*4*3=60
• 9 years agoHelpfull: Yes(1) No(0)
• 5p3 = 60.
  5 books for 3 child's.
• 9 years agoHelpfull: Yes(1) No(0)
• 5c3* 3! is the correct ans
  
• 8 years agoHelpfull: Yes(1) No(0)
• 5c3 ways !5/!3*!2
• 9 years agoHelpfull: Yes(0) No(0)
• what about the remaining 2 books ? they should also be distributed because books are not to be distributed equally...
• 9 years agoHelpfull: Yes(0) No(0)
• Ans: 60.
  
  5P3 = 60
• 9 years agoHelpfull: Yes(0) No(1)
• n distinct things can be divided in r distinct group in -> r^n ways
  so here n=5
  r=3
  so 3^5 is correct answer
  other way we can understand child may be contain 1 or 2 or 3 books
  so each book have 3 choice
  3*3*3*3*3=3^5 is answer
• 8 years agoHelpfull: Yes(0) No(0)
• factorial of 5
  
• 8 years agoHelpfull: Yes(0) No(0)
• Books can be given to the first child in 5 ways,second child in 4 ways and third child in 3 ways since the repetition is not possible here, otherwise solution should be 5^3.
  hence the solution is 5*4*3=60ways.
• 8 years agoHelpfull: Yes(0) No(0)
• There is no restriction on how many books a chiild can get. A child can get either no book or all 5 books.
  
  The first book can be distributed in 3 ways (can be given to any of the child)
  
  Similarly, the second book can be distributed in 3 ways (can be given to any of the child)
  
  .
  
  .
  
  The fifth book can be distributed in 3 ways (can be given to any of the child)
  
  So, total number of ways of distributing 5 books among 3 childrens = 3x3x3x3x3 = 243
• 7 years agoHelpfull: Yes(0) No(0)
• we can use n+r-1 c r-1 formula here..and the answer is 21
• 7 years agoHelpfull: Yes(0) No(1)
• "a" is the correct option
• 7 years agoHelpfull: Yes(0) No(1)
• ans is 60.
  Two ways to do this
  (i)
  (5c3)*3! = 60(by using formula)
  
  (ii)
  5*4*3=60 (by using simple logic)
• 2 years agoHelpfull: Yes(0) No(0)