ABCD is a rectangle. side AB is produced to E such that BC=BE. A circle is drawn with AE as diameter. The line BC is produced to meet the circumference of circle at point F.
What is the length of BF.
options I don't remember but it was given in term of l and b.

• As given in the question that BC produced meets the circumference of the circle that means BC must be the smaller side of the rectangle.
  
  Let the sides of the rectange ; AB = a and BC = b
  
  Radius of the circle will be : AE/2 = (AB + BE) /2 = (AB + BC) /2 = (a+b) /2
  
  Therefore OE = OF = (a + b) / 2
  
  OB = (OE - BE) = ( a + b ) / 2 - b = ( a - b ) /2
  
  Therefore; BF^2 = OF^2 - OB^2 = [(a + b) / 2 ]^2 - [(a - b) / 2 ]^2 = [( a + b +a - b )/ 2 ] x [ ( a + b - a + b )/ 2 ]
  
  =2a/2 x 2b/2 = ab
  therefore, BF=(ab)^(1/2)
• 8 years agoHelpfull: Yes(18) No(0)
• Sorry.. My above ans. Is wrong..its a calculation mistake.. √ab*BC will be ans.
  BF2= OF2-OB2 will be equation...
• 8 years agoHelpfull: Yes(4) No(0)
• Ans is: sqrt(AB*BC)
• 8 years agoHelpfull: Yes(2) No(0)
• Ans.√ab2+bc2/2
  We know that diameter =ab+be
  Let ab=x and be=y
  Radius=x+y/2
  SO, OF =X+Y/2
  and OB=OE-BE
  Now, OF2=OB2+BF2
  by putting all value and by solving above
  We get bf = √ab2+bc2/2
  
• 8 years agoHelpfull: Yes(2) No(1)
• length of BF is always in seconds,minute or hour if si unit is considered then in second.
  please specify the site from which you downloaded the BF ie from brazzers or naughty america etc.
• 8 years agoHelpfull: Yes(2) No(0)
• the answer to this question is sqrt(AB*BC)
• 8 years agoHelpfull: Yes(1) No(0)
• Please explain. I had also the same ques.
• 8 years agoHelpfull: Yes(0) No(0)
• x, y sides of rectangle AB=x and BC=y
  Ab is produced to E such that BC= BE THEN BE=Y
  AE as a diameter which we can represent as AB+BE= x+y
  Now circle is drawn with AE as diameter
  Now n is a point on line AE so when BC produced to meet the circumference of circle to point F, SO BF is a radius of circle so BF=x+y/2
• 8 years agoHelpfull: Yes(0) No(1)
• Ans:BF=AB
  Sol: Diameter =>AB+BE= CB+BF (given that BC=BE )
  So therefore AB=BF
• 8 years agoHelpfull: Yes(0) No(2)
• take length of rectngle=l, breath=b
  now radis of circle=(l+b)/2. so of =(l+b)/2, trangle obf is right trngle
  so,sqrt(of^2-ob^2)=bf
  now bf -bc=cf
  
• 8 years agoHelpfull: Yes(0) No(0)
• how bf is a radius of circle itz not given specifically that b is originating from center
• 7 years agoHelpfull: Yes(0) No(0)
• @ Jignesh Mishty don't to know how to talk to a girl!Even if Anjali is answering wrong ,no one gave u any right to act like a barbarian!It shows what ur level is ,you are a SAVAGE.Learn to be a decent and sophisticated guy!learn manners
• 7 years agoHelpfull: Yes(0) No(1)
• check this out:-
  http://www.logicguns.com/q/abcd-is-a-rectangle-side-ab-is-produced-to-e-such-that-bcbe-a-circle-is-drawn-with-ae-as-diameter-the-line-bc-is-produced-to-meet-the-circumference-of/5617da0a2b78726726a8a320/
• 6 years agoHelpfull: Yes(0) No(0)