Elitmus
Exam
Numerical Ability
Probability
P is an even number (I think greater than 2 it was given). e is the probability of number of even numbers divisible by p, o is the probability of number of odd number divisible by p and w is the probability of number of whole numbers divisible by p. Then which equation satisfies.
1. w=2 e
2. w=e/2
3. w=o/2
4. not remember
ask on 2nd aug
Read Solution (Total 5)
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- it was p>99
since p is an even number..so it can,t be divisible by odds
e is the probability of p to be divisible by even numbers..means there are only even numbers in sample space..n for w all whole numbers are allowed(odds also)
the possible number of values of p are same in both cases but
sample space(for w)=2(sample space for e)
so it is clear that w=e/2 - 9 years agoHelpfull: Yes(17) No(1)
- option 1 was correct.
- 9 years agoHelpfull: Yes(2) No(2)
- w=probability of(whole number/even number)
=prob of((even+odd)/even)
=prob of(even/even + odd/even)
=e + o
now we see an odd no can never be divisible by an even no
so, prob of(odd/even)=o=zero
therefore
w=e+zero
w=e - 9 years agoHelpfull: Yes(0) No(2)
- ans is b check
- 9 years agoHelpfull: Yes(0) No(0)
- 5C3 *3.This will be the answer.
- 5 years agoHelpfull: Yes(0) No(1)
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