Rajesh can finish 1/5 of his home work in one hour. Seema can finish 3/7 of
her homework in 90 minutes and Ramya can finish 3/4 of her homework in
three and a half hours. If all of them start their home work at 12.00 PM and can
go to play as soon as they all finish their homework. When can they start to
play, if they take a break at 3.30 PM for 30 minutes?

• 5:30pm bcoz highest time is taken by Rajesh to complete his homework I.e 5 hrs.....adding these 5 hrs from 12:00 noon and including the break. Ans may be 5:30 pm they can meet to play
• 9 years agoHelpfull: Yes(14) No(1)
• Starting homework at 12 PM and Taking a break at 3:30 PM, we came to know that each of them have already spent 3 hrs and 30 minute i.e 210 min
  After taking break, they started to do their homework at 4 PM
  1. Rajesh can finish 1/5 of his work in 1 hr. i.e in 60 min
  He can finish 1 work in 60* 5 = 300 min
  Remaining time to complete his hm work = 300-210= 90 min
  Starting again at 4 PM,he will finish his homework at 5:30 PM
  2. Sema can finish 3/7 of her homework in 90 min
  She will finish 1 work in 90*(7/3) = 210 min
  Therefore she finished her work at 3:30 PM
  3. Ramya can finish 3/4 of her work in 210 min
  She will finish 1 work in 210*(4/3 ) min= 280 min
  Remaining time left for Ramya to complete her work =280 - 210 = 70 min
  Starting to do homework again at 4 PM,she will complete her work at 5:10 PM
  Since Rajesh takes longer time to finish the work (completing the work at 5:30 PM), hence they all can start to play at 5:30 PM. That's the only time they all will meet
• 7 years agoHelpfull: Yes(12) No(1)
• rajesh can finish his work in 5 hr,
  ramya can finish her work in 4.7 hr
  seema can finish in 3.5 hr
  so after 5:30 they can go to play
• 9 years agoHelpfull: Yes(2) No(2)
• 1^3+1=2, 2^3+2=10, similarly 5^3+5=130
• 8 years agoHelpfull: Yes(0) No(0)