Elitmus
Exam
Logical Reasoning
Cryptography
AXM
LMP
............
VMSW
VFMX
XVSA
..............
VFFWLW
Asked in elitmus 16 Aug 2015
Read Solution (Total 12)
-
- 648
789
--------
5832
5184
4536
----------
511272 - 9 years agoHelpfull: Yes(2) No(0)
- 648
789
..............
5832
5184
4536
...............
511272 - 9 years agoHelpfull: Yes(2) No(0)
- AXM
LMP
............
VMSW
VFMX
XVSA
..............
VFFWLW
_ means some carry.
1.first see x+1=v.
2.Then check all the possibility for RM*M=MR.
if u did step 2 properly then u see, u are completed this problem 20 or 30%. because this time u know the value of X=4 so then v=5, M=8, p=9.
3.solve A48*8 = 5F84. try all possibility and u found F=1;
4.Solve 5+1+s = _1. then u found s=3.
5.Solve A48*8=5184. then u found a=6 and by solving M+M+A=w (8+8+6=2). that means w=2.
6.Solve 648*P=5832. Then u also found value of p=9.
so U got like this
648
* 789
--------------
5832
5184-
4536--
---------------
511272
--------------- - 9 years agoHelpfull: Yes(1) No(0)
- plzz explain cleary
- 9 years agoHelpfull: Yes(0) No(0)
- fist hint M.M =X.
secondly X+1=V
thus only 8.8=4 and 2.2=4 will satisfy the above two.
thus 8.8=4 will be the only one to get ans.
so 648*789. ans - 9 years agoHelpfull: Yes(0) No(2)
- M#8, P#9, X#4, A#6, L#7, V#5, S#3, W#2, F#1.
- 9 years agoHelpfull: Yes(0) No(1)
- fist hint M.M =X.
secondly X+1=V
third hint m.x=m
use 8.8=64 - 9 years agoHelpfull: Yes(0) No(1)
- A=6,x=4,M=8,L=7,p=9,v=5,w=2,F=1
- 9 years agoHelpfull: Yes(0) No(0)
- A X M 6 4 8
L M P 7 8 9
V M S W 5 8 3 2
V F M X 5 1 8 4
X V S A 4 5 3 6
V F F W L W 5 1 1 2 7 2
- 9 years agoHelpfull: Yes(0) No(0)
- 648
* 789
---------
5832
5184
4536
----------
511272 - 9 years agoHelpfull: Yes(0) No(0)
- 648
789
____
5832
5184
4536
_______
511272 - 9 years agoHelpfull: Yes(0) No(0)
- Hi,
In this XM*M=MX ,
First we find M and X values
Take M=8
x(8)*8=_4 (i.e the x values is 4 bcoz XM*M=MX) Then
Now we know the X=4 & M=8
Now replace the x and M values
X+carry=V (When add two single digit no's that gives a carry '1' that number >4)
4+1=V
V=5;
then replace 'v' value .
(AXM*M=VFMX)
A48*8=5F84
try A value then multiply with 8 i.e 5_84 ,which is value of between 5 and 8
A=6 648*8=5184 ,Now we get two more values A=8 and F=1.
(AXM*L=XVSA)
648*L=45S6 ,then find the S value with the help of 648 and L =7
648*7=4536 ,S=3
(AXM*P=VMSW)
648*P=583W multiply 648*_=583_;
648*9=5832 ,Now P=9 & W=2
Now replace all values
Ans is
511272
- 8 years agoHelpfull: Yes(0) No(0)
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