ram borrows rs.8000 at 12% p.a. simple interest and mohan borows rs.9100 at 10% p.a. simple interest. in how many years will their borrowed amounts(dept) be equal?

• 8000+(8000*12*x)/100 = 9100+(9100*10*x)/100
  x is time in years at which two amounts will be equal
  solving we get x = 22
• 8 years agoHelpfull: Yes(3) No(3)
• I want to explain Santhi Priya's answer::
  Simple Interest = P*R*T/100 = 8000*12*T/100 = 960T
  and total amount of A is = 8000 + S.I. = 8000 + 960T
  and this procedure can be followed same for B.
• 6 years agoHelpfull: Yes(2) No(1)