amir has 3 desert every sunday...he stocked up 10 different chocolates and 12 diff icecreams,given that he never has same combination and doesn't 3 chocolates nor 3 icecreams,how many sundays it requires for his stock to be over?

a)1045 b)1200 c)2400 d)7200

• he either can can have 2 chocolates and 1 icecream or 1 chocolate and 2 icecream.
  so the solution would be.
  10C2*12C1 + 10C1*12C2 = 1200
• 8 years agoHelpfull: Yes(37) No(0)
• year correct sachin
  
  Case 1: Permutation for choosing 1 choclate & 2 Icecream = 10C1*12C2 = 660
  OR
  Case 2: Permutation for choosing 2 choclate & 1 Icecream = 10C2*12C1 = 540
  
  total = case 1 + case 2 = 1200
• 8 years agoHelpfull: Yes(6) No(0)
• (# of ways of combining 10 choc and 12 icecream )-(# of ways of combining only choc)-(# of ways of combining only icecream)
  =22c3-10c3-12c3
  =1540-120-220
  =1200
• 8 years agoHelpfull: Yes(2) No(1)
• i thik ..
  2 choc and 1 icecrm or 2 icecrm 1 choc
  so 10*9*12+12*11*10=2400 ans c.
• 8 years agoHelpfull: Yes(1) No(13)
• but no same combination
• 8 years agoHelpfull: Yes(0) No(0)
• no same combination is taken in that solution.
• 8 years agoHelpfull: Yes(0) No(0)
• 1200 is wrong answer....
• 8 years agoHelpfull: Yes(0) No(1)
• ADITI 's soln is correct 2400 nice
  
• 8 years agoHelpfull: Yes(0) No(2)
• Any more solutions or explanations to this ? Rakesh ????
• 8 years agoHelpfull: Yes(0) No(0)