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n is a natural number and n^3 has 16 factors.Then how many factors can n^4 have?
Read Solution (Total 9)
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- answer..25
no. of factors of (a^m)(b^n) = (m+1)(n+1)
now,
16= 4*4 = (3+1)(3+1)
suppose (2^3)(3^3) will be equal to 6^3
so n = 6
now, 6^4 = (2^4)(3^4)
FACTOR = (4+1)(4+1) = 25 - 9 years agoHelpfull: Yes(3) No(0)
- given n^3 has 16 factors
we know that x^k has k+1 factors
=>n^3=(somevalue)^5*3=(some value)^15
similalrly n^4=(somevalue)^5*4
= 5*4=20+1 = 21 factors - 9 years agoHelpfull: Yes(2) No(0)
- n^3 has 16 factor that is 4*4
similarly n^4 has 25 factor as 5*5
- 9 years agoHelpfull: Yes(2) No(0)
- What is the right ans??
- 9 years agoHelpfull: Yes(0) No(0)
- n=8
8^4
25 - 9 years agoHelpfull: Yes(0) No(0)
- answer is 25 factors
- 9 years agoHelpfull: Yes(0) No(0)
- factors 16=4*4
so,3,3 in cube,
so n^4 3+1,3+1=4,4 so 4+1*4+4
25.so answer is 25 - 9 years agoHelpfull: Yes(0) No(0)
- let us take n=2*x (you can take any number in place of 2)
n^3 means 2^3 *x^3 so (3+1)*(3+1) =16 factors are present
n^4 means 2^4 * x^4 so (4+1)*(4+1)=25 factors - 9 years agoHelpfull: Yes(0) No(0)
- So, for Y=3, we have number of factors=16.
Which means (3+1)^X=16=> X=2.
Now putting Y=4, we get (Y+1)^X=(4+1)^2= 25 factors.
Hence we can say that N has atmost 25 factors. - 9 years agoHelpfull: Yes(0) No(0)
TCS Other Question
You have been given a physical balance and 7 weights of 52, 50, 48, 44, 45, 46, and 78 Kgs.. Keeping weights on one pan and object on the other, what is the maximum you can weigh less than 183 Kgs.?
a)178
b)180
c)181
d)182
There are 5 distinct integers a, b, c, d, e in ascending order.
(68-a)(68-b)(68-c)(68-d)(68-e) = 725.
What is a + b + c + d?